Understanding the Problem:
The question asks how to find the sum of all elements in an array that match a certain condition, typically being integers.
Breaking Down the Problem:
- Array: A collection of elements (numbers, strings, etc.) stored in an ordered list.
- Integer Elements: Numbers without a decimal (e.g., 1, -2, 100, etc.).
- Matching Condition: We are looking for elements that are integers.
- Total: We need to calculate the sum of all the matching integer elements in the array.
Step-by-Step Approach:
- Step 1: Go through each element in the array.
- Step 2: Check if the element is an integer.
- Step 3: If it’s an integer, add it to a running total.
- Step 4: Continue until you’ve checked all the elements in the array.
- Step 5: Return the total sum of all integers.
Example:
Let’s say we have an array [1, "hello", 5, 3.5, -2, 10]
.
- Step 1: Start with the first element:
1
. It’s an integer, so add it to the total (Total = 1). - Step 2: The next element is
"hello"
, which is not an integer, so skip it (Total = 1). - Step 3: The next element is
5
. It’s an integer, so add it to the total (Total = 1 + 5 = 6). - Step 4: The next element is
3.5
, which is not an integer, so skip it (Total = 6). - Step 5: The next element is
-2
. It’s an integer, so add it to the total (Total = 6 + (-2) = 4). - Step 6: The last element is
10
. It’s an integer, so add it to the total (Total = 4 + 10 = 14).
The total of the matching integer elements is 14.
Code in Different Languages:
Python:
def sum_of_integers(arr):
total = 0
for element in arr:
if isinstance(element, int): # Check if element is an integer
total += element # Add integer to the total
return total
# Example
arr = [1, "hello", 5, 3.5, -2, 10]
print("Total sum of integers:", sum_of_integers(arr))
JavaScript:
function sumOfIntegers(arr) {
let total = 0;
for (let element of arr) {
if (Number.isInteger(element)) { // Check if element is an integer
total += element; // Add integer to the total
}
}
return total;
}
// Example
let arr = [1, "hello", 5, 3.5, -2, 10];
console.log("Total sum of integers:", sumOfIntegers(arr));
Java:
public class SumOfIntegers {
public static int sumOfIntegers(Object[] arr) {
int total = 0;
for (Object element : arr) {
if (element instanceof Integer) { // Check if element is an integer
total += (Integer) element; // Add integer to the total
}
}
return total;
}
public static void main(String[] args) {
Object[] arr = {1, "hello", 5, 3.5, -2, 10};
System.out.println("Total sum of integers: " + sumOfIntegers(arr));
}
}
C++:
#include <iostream>
#include <vector>
#include <typeinfo> // For type checking
using namespace std;
int sumOfIntegers(vector<any> arr) {
int total = 0;
for (auto &element : arr) {
if (element.type() == typeid(int)) { // Check if element is an integer
total += any_cast<int>(element); // Add integer to the total
}
}
return total;
}
int main() {
vector<any> arr = {1, "hello", 5, 3.5, -2, 10};
cout << "Total sum of integers: " << sumOfIntegers(arr) << endl;
}
Steps for Each Language:
- Loop through each element in the array.
- Check if the element is an integer using the specific language’s method (
isinstance()
in Python,Number.isInteger()
in JavaScript,instanceof Integer
in Java, etc.). - Add to the total if it’s an integer.
- Return the final sum.
This approach keeps the logic simple and ensures the task is completed in a straightforward manner.