Understanding the Problem:

The question asks how to find the sum of all elements in an array that match a certain condition, typically being integers.

Breaking Down the Problem:

  • Array: A collection of elements (numbers, strings, etc.) stored in an ordered list.
  • Integer Elements: Numbers without a decimal (e.g., 1, -2, 100, etc.).
  • Matching Condition: We are looking for elements that are integers.
  • Total: We need to calculate the sum of all the matching integer elements in the array.

Step-by-Step Approach:

  1. Step 1: Go through each element in the array.
  2. Step 2: Check if the element is an integer.
  3. Step 3: If it’s an integer, add it to a running total.
  4. Step 4: Continue until you’ve checked all the elements in the array.
  5. Step 5: Return the total sum of all integers.

Example:

Let’s say we have an array [1, "hello", 5, 3.5, -2, 10].

  • Step 1: Start with the first element: 1. It’s an integer, so add it to the total (Total = 1).
  • Step 2: The next element is "hello", which is not an integer, so skip it (Total = 1).
  • Step 3: The next element is 5. It’s an integer, so add it to the total (Total = 1 + 5 = 6).
  • Step 4: The next element is 3.5, which is not an integer, so skip it (Total = 6).
  • Step 5: The next element is -2. It’s an integer, so add it to the total (Total = 6 + (-2) = 4).
  • Step 6: The last element is 10. It’s an integer, so add it to the total (Total = 4 + 10 = 14).

The total of the matching integer elements is 14.

Code in Different Languages:

Python:

def sum_of_integers(arr):
    total = 0
    for element in arr:
        if isinstance(element, int):  # Check if element is an integer
            total += element  # Add integer to the total
    return total

# Example
arr = [1, "hello", 5, 3.5, -2, 10]
print("Total sum of integers:", sum_of_integers(arr))

JavaScript:

function sumOfIntegers(arr) {
    let total = 0;
    for (let element of arr) {
        if (Number.isInteger(element)) {  // Check if element is an integer
            total += element;  // Add integer to the total
        }
    }
    return total;
}

// Example
let arr = [1, "hello", 5, 3.5, -2, 10];
console.log("Total sum of integers:", sumOfIntegers(arr));

Java:

public class SumOfIntegers {
    public static int sumOfIntegers(Object[] arr) {
        int total = 0;
        for (Object element : arr) {
            if (element instanceof Integer) {  // Check if element is an integer
                total += (Integer) element;  // Add integer to the total
            }
        }
        return total;
    }

    public static void main(String[] args) {
        Object[] arr = {1, "hello", 5, 3.5, -2, 10};
        System.out.println("Total sum of integers: " + sumOfIntegers(arr));
    }
}

C++:

#include <iostream>
#include <vector>
#include <typeinfo>  // For type checking

using namespace std;

int sumOfIntegers(vector<any> arr) {
    int total = 0;
    for (auto &element : arr) {
        if (element.type() == typeid(int)) {  // Check if element is an integer
            total += any_cast<int>(element);  // Add integer to the total
        }
    }
    return total;
}

int main() {
    vector<any> arr = {1, "hello", 5, 3.5, -2, 10};
    cout << "Total sum of integers: " << sumOfIntegers(arr) << endl;
}

Steps for Each Language:

  1. Loop through each element in the array.
  2. Check if the element is an integer using the specific language’s method (isinstance() in Python, Number.isInteger() in JavaScript, instanceof Integer in Java, etc.).
  3. Add to the total if it’s an integer.
  4. Return the final sum.
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This approach keeps the logic simple and ensures the task is completed in a straightforward manner.

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